aptitude tricks 1

hi friends, i want to share some of the tricks on how to solve aptitude questions quickly.there are few points to remember:
1)There are no tricks which are unanimous.
2)You need to practice as many questions as you can and than have to make tricks which are suitable to you accordingly as mind level and level of preparation along with interests does vary from person to person so unanimous tricks won't do ...

3)The tricks also varies from questions to questions , so it won't be possible to provide you tricks for each and every type but you can post some type of questions over here and i will try to elaborate tricks to you as much as possible as i have also given such tests ...

4)You need to practice as much tests as possible before your exam and that will be suffice 

let us today discuss about train problems:

first let us solve a basic question.

1.	A train running at the speed of 60 km/hr crosses a pole in 9 seconds. What is the length of the train?
	A. 120 metres B. 180 metres C. 324 metres D. 150 metres

this is the simplest question you can get in trains problem..read the question and you now know that speed and time is given and you need to find out length i.e. distance.we know the formula for distance which is speed *time. the only problem is that speed is given in km/hr and time in second.this is one of the common mistake we usually do.we should solve only when units are in same system.now we can either convert speed into m/sec or time into hour.but converting speed is more easy coz we need to multiply only by 5/18.

if you don't know how this 5/18 came then this is the explanation:

1 km=1000metre

1hr=60*60 seconds=3600 seconds

so, km/hr=1000/3600m/sec=5/18m/sec

 when we convert from km/hr to m/sec we multiply by 5/18 and when we convert from m/sec to km/hr we multiply by 18/5

now the solution

Speed=		60 x	5	m/sec	=		50	m/sec.
			18				3

Length of the train = (Speed x Time) =		50	x 9	m = 150 m.
		3

NOW, if instead of stationary object like a pole,if there is some moving object like man,car etc.

2.  A train 125 m long passes a man, running at 5 km/hr in the same direction in which the train is going, in 10 seconds. The speed of the train is: A. 45 km/hr B. 50 km/hr C. 54 km/hr D. 55 km/hr

in this question train's length and time to cross the man is given.this problem would have been same like the

above problem if the man would have been stationary. before we solve the question let us understand the concept of same direction and opposite direction.let us take an example, the distance between A and B is 100 km.

 CASE 1: a car from A starts moving at speed of 50 km/hr towards B and the car at B starts moving at speed 30 km/hr in same direction as of car from A was moving i.e. opposite to A.now the time required for the two trains to meet will be 100/(50-30)=5hr coz in the same direction the relative speed is the difference of two speed.

 CASE 2:if the car from B was moving toward A then the time required would be 100/(50+30)=1.125hr coz in opposite direction the relative speed is the sum of two speed.

NOW the solution:

Speed of the train relative to man =		125	m/sec
		10

=		25	m/sec.
		2

=		25	x	18	km/hr
		2		5

   = 45 km/hr.
Let the speed of the train be x km/hr. Then, relative speed = (x - 5) km/hr.
x - 5 = 45         x = 50 km/hr.

NOW LET ME GIVE YOU SOME IMPORTANT FORMULAS:

1. Time taken by a train of length l metres to pass a pole or standing man or a signal post is equal to the time taken by the train to cover l metres.
   
2. Time taken by a train of length l metres to pass a stationery object of length b metres is the time taken by the train to cover (l + b) metres.
   
3. Suppose two trains or two objects bodies are moving in the same direction at u m/s and v m/s, where u > v, then their relative speed is = (u - v) m/s.
   
4. Suppose two trains or two objects bodies are moving in opposite directions at u m/s and v m/s, then their relative speed is = (u + v) m/s.
   
5. If two trains of length a metres and b metres are moving in opposite directions at u m/s and v m/s, then:

          The time taken by the trains to cross each other =(a+b)/(u+v)sec

      6.If two trains of length a metres and b metres are moving in the same direction at u m/s and v m/s, then:
           The time taken by the faster train to cross the slower train =(a+b)/(u-v)sec

       7.If two trains (or bodies) start at the same time from points A and B towards each other and after     

          crossing they take a and b sec in reaching B and A respectively, then

          (A's speed) : (B's speed) =square root of a: square root of b

     
        now will discuss further topics in another blog:)

facebook timeline

There is a way, ladies and gentlemen, you get yourself aboard an early developers look at Facebook’s new layout, that being the one called Timeline that we were introduced to recently. The process is relatively simple, though you must be warned: its designed to allow developers to see the build early and may not be completely set up to show you exactly what you want to see of yourself – my god, your whole Facebook life, right there! Let’s get started!

First, you must head to the Facebook Developers page at https://developers.facebook.com/ and sign up for an account. This will be the longest portion of your process as you may have to wait for permissions to take effect or for your confirmation numbers to go through. You’ve got to confirm your account with a text message sent to your cell phone, at which point you’ve got to head to step two.

Second, create a new app. To do this you’ve just got to head up to the upper right-hand side of your developer homepage and hit the Create New App button. You’ll have a window pop up with a place for App Display Name and App Namespace. Enter whatever you like and click Continue. There may be a “type this picture” security check at this point – do it and continue.

Third, once you’re in the App Summary for the app you’ve just started creating, find the link in the upper left that’s titled “Open Graph”. You’ll recognize this link from yesterday’s news. Here you’ve got to enter something basic in both text fields, something like Watch and Movie will do fine. Hit “get started.”

Fourth, you’ll be brought back to a page that looks basically like the page you were at before you hit Open Graph. All you’ve got to do here is go to the bottom of the screen and hit “Save Changes and Next”. At this point you wait for a few minutes.

Fifth and finally, head to your own normal Facebook homepage and you’ll hopefully see this little box front and center. Hit “Get it Now” and you’re in!

Also check out our full Timeline guide if you wanna know how to get around n such. Futuristic!

UPDATE: Note that it will only be you and other Facebook Developers (including everyone else who used this method to activate, in this case) that will be able to see your Timeline until the 30th of September, 2011. It appears that this is the date that Timeline will be active for everyone OR at least the date at which the Beta will begin to be sent out in bulk.